For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023..06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
To convert moles to grams, we need to use the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Therefore, 1.25 mol of NaOH would be equal to 1.25 mol * 40 g/mol = 50 grams of NaOH.
To find the mass of 3.50 mol of LiBr, first calculate the molar mass of LiBr, which is 86.845 g/mol. Then, multiply the molar mass by the number of moles: 86.845 g/mol * 3.50 mol = 303.9575 g. Therefore, the mass of 3.50 mol of LiBr is 303.96 grams.
The molar mass of H2 is 2 g/mol. To find the mass of 5 moles of H2, you would multiply the molar mass by the number of moles: 2 g/mol * 5 mol = 10 grams.
To calculate the mass of 4.75 mol of copper (II) nitrate, you need to first find the molar mass of Cu(NO3)2 which is 187.55 g/mol. Then, multiply the molar mass by the number of moles (4.75 mol) to get the mass: 187.55 g/mol * 4.75 mol = 890.56 grams. So, the mass of 4.75 mol of copper (II) nitrate is 890.56 grams.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023..06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
To find the mass in grams of 6.25 mol of copper(II) nitrate (Cu(NO3)2), you need to first calculate the molar mass of the compound using the periodic table. The molar mass of Cu(NO3)2 is 187.56 g/mol. Multiply the molar mass by the number of moles to find the mass: 6.25 mol * 187.56 g/mol = 1172.25 grams.
To convert moles to grams, we need to use the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Therefore, 1.25 mol of NaOH would be equal to 1.25 mol * 40 g/mol = 50 grams of NaOH.
2 moles of Iodine is equal to 253.8 grams, which is the molar mass of Iodine (I). This can be calculated by multiplying the molar mass of Iodine (126.9 g/mol) by the number of moles (2 moles).
To find the mass of 3.50 mol of LiBr, first calculate the molar mass of LiBr, which is 86.845 g/mol. Then, multiply the molar mass by the number of moles: 86.845 g/mol * 3.50 mol = 303.9575 g. Therefore, the mass of 3.50 mol of LiBr is 303.96 grams.
The molar mass of H2 is 2 g/mol. To find the mass of 5 moles of H2, you would multiply the molar mass by the number of moles: 2 g/mol * 5 mol = 10 grams.
The molar mass of ethyl alcohol (C2H5OH) is 46.07 g/mol. Therefore, the mass of 2 moles of ethyl alcohol would be 92.14 grams (46.07 g/mol x 2 mol).
To calculate the mass of 4.75 mol of copper (II) nitrate, you need to first find the molar mass of Cu(NO3)2 which is 187.55 g/mol. Then, multiply the molar mass by the number of moles (4.75 mol) to get the mass: 187.55 g/mol * 4.75 mol = 890.56 grams. So, the mass of 4.75 mol of copper (II) nitrate is 890.56 grams.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
The gram formula mass for Ca3(PO4)2 is calculated by adding up the atomic masses of each element in the compound. For calcium (Ca), the atomic mass is 40.08 g/mol, for phosphorus (P) it is 30.97 g/mol, and for oxygen (O) it is 16.00 g/mol. Multiplying each atomic mass by the number of atoms in the compound and adding them up gives a gram formula mass of approximately 310.18 g/mol.
The molar mass of water (H2O) is approximately 18.02 g/mol. To find the mass of 2.00 mol of water, you would multiply the molar mass by the number of moles: 2.00 mol * 18.02 g/mol = 36.04 grams.