The molar mass of carbon is approximately 12 grams/mol. Therefore, the mass of 2 moles of 12C is 24 grams (12 g/mol x 2 mol).
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023..06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
The molar mass of H2 is 2 g/mol. To find the mass of 5 moles of H2, you would multiply the molar mass by the number of moles: 2 g/mol * 5 mol = 10 grams.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023..06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
To find the mass in grams of 6.25 mol of copper(II) nitrate (Cu(NO3)2), you need to first calculate the molar mass of the compound using the periodic table. The molar mass of Cu(NO3)2 is 187.56 g/mol. Multiply the molar mass by the number of moles to find the mass: 6.25 mol * 187.56 g/mol = 1172.25 grams.
To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
mol = mass/Mr rearrange mol x Mr = mass 2 x 126.9g = 253.8g
step 1: calculate the molar mass of one molecule LiBr by adding together their amu (atomic mass units) step 2: 3.50 mol * ( molecular mass LiBr / 1 mol LiBr ) = grams LiBr amu on your periodic table is grams when you have one mol of that substance
The molar mass of ethyl alcohol (C2H5OH) is 46.07 g/mol. Therefore, the mass of 2 moles of ethyl alcohol would be 92.14 grams (46.07 g/mol x 2 mol).
The molar mass of H2 is 2 g/mol. To find the mass of 5 moles of H2, you would multiply the molar mass by the number of moles: 2 g/mol * 5 mol = 10 grams.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
To calculate the mass of 4.75 mol of copper (II) nitrate, you need to first find the molar mass of Cu(NO3)2 which is 187.55 g/mol. Then, multiply the molar mass by the number of moles (4.75 mol) to get the mass: 187.55 g/mol * 4.75 mol = 890.56 grams. So, the mass of 4.75 mol of copper (II) nitrate is 890.56 grams.
Ca = 40 x 3 = 120 grams P = 31 x 2 = 62 grams O = 16 x 8 = 128 grams Add them together and you have 310 grams. This is the mass in grams of your formula. It is expressed in grams/mole because 310 is the weight of one mole of Ca3(PO4)2.
0.8 moles HNO3 (63.018 grams/1 mole HNO3) = 50 grams nitric acid ===============