2g/cm3
The idea is to divide the mass by the volume.
density = mass / volume density = 0.250 kg / (0.05 m)3 density = 0.250 kg / 0.000125 m3 density = 2000 kg/m3 (For comparison, pure water's density is about 1000 kg/m3)
Marshmallows vary in density. They are not a pure substance. As they contain air bubbles their density can be altered merely by squeezing them as can their volume but their mass would be the same even if smashed into pieces. The marshmallow's physical dimensions would change.
Pure water at standard temperature and pressure has density of 1 kg/L.1.2 Liter = 1.2 kg
Approximately 6g. The density of pure water at 20 degrees centigrade and standard atmospheric pressure is 1 g/ml. The answer is approximate since the water may not be chemically pure and you do not give a temperature or pressure.
Density= mass/volumeDensity=820g/350cm3Density= 2.34g/cm3
The density is 10.7 g/mL. The sample is not pure lead because the density of pure lead is 11.3 g/mL.
2.34285714g/cm3
The idea is to divide the mass by the volume.
Mass and volume are extensive properties, which are dependent upon the size of the sample. A larger sample will have a greater mass and volume than a smaller sample. Density is an intensive property, which does not depend on the size of the sample. Density is a ratio of mass to volume, which does not vary with the size of the sample. The density of a larger sample will be the same as the density of a smaller sample.
Start by writing the formula that you probably know for density D=m/V Now plug in the data that you have: 2.336 g/cm3 = m/350 cm3 so, m = 350 x 2.336 = 817.6 g
The **density** of a substance is defined as its mass per unit volume. We can calculate the density using the formula: [ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} ] Given that the sample has a volume of **50 cm³** and a mass of **135 g**, let's determine the density: [ \rho = \frac{135 , \text{g}}{50 , \text{cm³}} ] The calculated density is approximately **2.7 g/cm³**[^10^]. Now let's compare this value to known densities: **Gold**: Gold has a density of *19.3 g/cm³*⁷. The sample's density is significantly lower. **Pure Water**: The density of pure water is approximately **1 g/cm³** at 4.0°C (39.2°F) . The sample's density is higher than water. **Aluminum**: Aluminum has a density of *2.7 g/cm³*[^10^]. The sample's density matches that of aluminum. **Ocean Water**: Ocean water contains dissolved salts, which increase its density. Seawater density typically ranges from *1.02 g/cm³ to 1.03 g/cm³*. The sample's density is higher than seawater. Based on the calculated density, the sample is most likely **aluminum**.
A cubic centimeter of pure water at maximum density has a mass of what?
One way of determining if a sample of gold is pure, would be to compare the density with that of real gold.
One way of determining if a sample of gold is pure, would be to compare the density with that of real gold.
The atomic mass of B is 10.8Amount of B = mass of pure sample/molar mass = 31.78/10.8 = 2.94mol There are 2.94 moles of the element boron in a 31.78g pure sample.
The density of water at standard temperature and pressure is 1 gram/milliliter. The size of the sample is irrelevant. If the sample is pure, then one drop of it has the same density as a tankerful of it has.