If density = mass/volume
and 1 litre = 1000cm3 (in your case 274L = 274000cm3)
since we now know the density and the volume we can arrange our density equation to make mass the subject...
mass = density x volume
therefore; mass = 1.025 x 274000 = 280850g = 280.850 kg
Answer (2818.75 g) 275 L is 2750 cm3 => 2750cm3 * desity of seawater (1.025 g/cm 3) is 2818.75 g
512.5 g
There are 2.2 pounds in a Kg.1025 lbs = 465.91kg
In order to find how many Moles of He are 1.20 x 1025 atoms of He, you need to divide 1.20 x 1025 atoms by the Avagadro's number (6.022 x 1023) The answer is 19.9 moles of He.
The volume of the Earth's oceans is about 1.3 x 1018 m3. Take the density of seawater to be about 1025 kg m-3, and the percentage mass of salt to be 3.5%. This gives a mass of salt of: 1.3 x 1018 x 1025 x 0.035 = 4.66375 x 1019 kg. ---- For the second, let's just include all of the Earth's crust that is above sea level. The average height of land above sea level is, according to John Murray, 686 m. The total land area is 1.489 x1014 m2. This gives a volume of 1.0217 x 1017 m3. The density of all that rock and soil is about 2700 kg m-3, so its mass comes to 2700 x 1.0217 x 1017 = 2.76 x 1020 kg. This is just under six times more than the mass of dissolved salt in the oceans.
3.05 x 1025
123
It absorbs the extra salt and becomes more dense. Normal salt water has a density of 1025 Kg/M3.
The mass of silicon is 4 659 g.
The population density of The Netherlands is roughly 1025 people per square mile.
0.0029
1027
The density of blood plasma is approximately 1025 kg/m3 and the density of blood cells circulating in the blood is approximately 1125 kg/m3. Blood plasma and its contents is known as whole blood. The average density of whole blood for a human is about 1060 kg/m3.
1025 is a multiple of 5.
1 + 5 + 25 + 41 + 205 + 1025 = 1,302
1025 x 50 = 51,250
689
The average density of pure ice is about 920 kg/m³. The average density of seawater is about 1025 kg/m³. By Archimedes's principle, the mass of the seawater displaced (i.e. the amount of the iceberg underwater) should equal the mass of the iceberg. Using that principle, for each 1 m³ of seawater displaced it takes 1025 kg of ice - which will have a volume of 1025 kg x 1 m³/920 kg = 1.114 m³. In other words, 1m³ of the iceberg is submerged for every 1.114 m³ of iceberg. 1/1.114 = 0.89756 So, on average about 90% of the iceberg is submerged. If the seawater is a little less salty, more of the iceberg is submerged. If the iceberg is "dirty" - with stuff in it that is more dense than ice, more of the iceberg is submerged. If the iceberg has voids (air pockets) it will be less dense and less of the iceberg is submerged.
There are 1000 metres in one kilometre. Therefore, 1025 kilometres is equal to 1025 x 1000 = 1025000 metres.