To answer this we need also the density of the sponge material.
1/3 gram per CC
Density = Mass/Volume = M/(L*H*W) = 10/(58*24*20) = 10/27840 = 0.00036 grams per cm3. This is totally unlikely since even light balsa has a density of more than 0.1 g/cm3
It depends what shape the prism is ! A cuboid prism would be 24 cm3 - while a triangular prism with those measurements would be half the volume.
Density = Mass/Volume = 100 grams / 4 mL = 24 grams per mL.
Volume = pi*122*24 = 10857.344 cubic inches to 3 d.p.
If a bar of copper has a mass of 216g and a volume of 24 cm3 then its density is 9 g/cm.
Density = Mass/Volume = 48g/24cm3 = 2 grams per cm3
1/3 gram per CC
The answer is 2 g/cm3How to figure out: When figuring out these things, the best hint is looking at what kind of answer you expect. In this case you are looking for density: weight (g) per volume (cm3). This is denoted as g/cm3. In words that is "g divided by cm3". So you divide 24 g by 12 cm3.24 g / 12 cm3 = 2 g/cm3.
A sphere with a radius of 24 cm has a volume of 57,905.84 cm3
2*3*4 = 24 cm3
24 cm3
1.25 Volume should be expressed in volumetric units. If you mean 3.20cm3, then since density is mass per unit volume, in this case (4gm)/3.2cm3)=1.25gm/cm3.
find number of moles of it(assume rtp) => 20/24 = ?find molar mass by dividing 226 by ur ans above. compare the molar mass found with the periodic table.
Determine the value of log 3 81 If A B n(A) 4, n(B) 7 the n(A B) = The product of the zeros of the polynomial 7 10 2 x x is A) B) C) D) If the system of equations 4x 5y 9, 8x ky 18 has infinitely many solutions then k = A) 8 B) 9 C) 10 D) 1 The discriminant of 2 5 3 0 2 x x is A) 1 B) C) 25 D) 24
24 cm3
An object with a mass of 24 g and a volume of 8 cc has a density of 3 g/cc