To answer this we need also the density of the sponge material.
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∙ 13y ago1/3 gram per CC
Density = Mass/Volume = M/(L*H*W) = 10/(58*24*20) = 10/27840 = 0.00036 grams per cm3. This is totally unlikely since even light balsa has a density of more than 0.1 g/cm3
It depends what shape the prism is ! A cuboid prism would be 24 cm3 - while a triangular prism with those measurements would be half the volume.
Density = Mass/Volume = 100 grams / 4 mL = 24 grams per mL.
Volume = pi*122*24 = 10857.344 cubic inches to 3 d.p.
The density of the rock is 20 grams/cm3. You can calculate density by dividing the mass by the volume.
Density = Mass/Volume = 48g/24cm3 = 2 grams per cm3
If a bar of copper has a mass of 216g and a volume of 24 cm3 then its density is 9 g/cm.
1/3 gram per CC
The answer is 2 g/cm3How to figure out: When figuring out these things, the best hint is looking at what kind of answer you expect. In this case you are looking for density: weight (g) per volume (cm3). This is denoted as g/cm3. In words that is "g divided by cm3". So you divide 24 g by 12 cm3.24 g / 12 cm3 = 2 g/cm3.
A sphere with a radius of 24 cm has a volume of 57,905.84 cm3
2*3*4 = 24 cm3
24 cm3
The density of the object is 2 grams per cubic centimeter (g/cm³). This is calculated by dividing the mass (24 grams) by the volume (12 cubic cm).
find number of moles of it(assume rtp) => 20/24 = ?find molar mass by dividing 226 by ur ans above. compare the molar mass found with the periodic table.
24 cm3
Density = Mass/Volume = M/(L*H*W) = 10/(58*24*20) = 10/27840 = 0.00036 grams per cm3. This is totally unlikely since even light balsa has a density of more than 0.1 g/cm3