The total allowable load in amps on a branch circuit by Code is 80 per cent of the circuit rating. Therefore, a 20 amp circuit shouldn't be loaded over 16 amps total.
Cannot answer this question. Will need to know the voltage and amperage of the circuit. Also need to know the application i.e. is it a lighting circuit or a motor circuit?
A series resonant circuit has it's reactive components connected in series with each other; while the reactive components, as in a "tank" circuit, are connected in parallel with each other. The resonant series circuit has the capability of producing usable increased voltage levels across each component at resonance, while the resonant tank circuit does not. The resonant parallel, or "tank" circuit; has the dual capability of creating a situation whereby the input amperage level is reduced to minimum while, at the same time, a maximum amount of circulating amperage is created between the two reactive tank components at resonance.
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You cannot increase amperage without changing voltage or resistance. Ohm's law states that voltage is current times resistance. You cannot change one alone. Not even changing frequency in a capacitive or inductive circuit will do this, because changing frequency represents a change in reactance, which is effectively a change in resistance.
This cannot be answered without knowing what size load you are connecting to the circuit. In the absence of a load, with a dead short, you will get a flow of amps at the maximum that the power supply can provide. I have no way of knowing what that is.
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An open circuit.
No. The breaker must protect the circuit components such as wiring, outlets and switches that are connected to the breaker. Therefore if you have a 30 amp circuit as dictated by its components you need to protect it with a 30 amp or less breaker.
minimum is '0' and maximum cannot be defined
That which you cannot (are not allowed to) do.
Current cannot flow through an open circuit.