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What is the measure of a side of a square whose diagonal is 4 inches longer than its side?
Wiki User
∙ 12y ago
Let a side of the square be x and its diagonal x+4:-
Using Pythagoras' theorem:
2x2 = (x+4)2
2x2 = x2+8x+16
Subtract x2+8x+16 from both sides:
x2-8x-16 = 0
Using the quadratic equation formula to solve the above gives x a positive value of 9.65685425
Therefore the sides are 9.65685425 inches and the diagonal is 13.65685425 inches.
Check: 2*9.656854252 = 186.509668 and the square root of this is 13.65685425
Wiki User
∙ 12y ago
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