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Q: What is the median in these numbers 101 103 106 108 110 110 112 130?

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103 is the only one.

106 is the median, as it is the number halfway between the two values, or half of the total of the two numbers.

3

mean: 104.4 median: 104 mode: 104 range: 5

Ruthenium isotopes are: Ru-96, 98, 99, 100, 101, 102, 103, 104, 106.

The median of the numbers is equal to the number in the middle when all are arranged in numerical order. In this case, the median number is 99.

(0/101) + (0/102) + (1/103) + (0/104) + (0/105) + (1/106)

No, it does not.

1 undecillion and one,1 undecillion and two,1 undecillion and three,etc.Or do you mean in terms of the next power of a million (on the long scale) or thousand (on the long scale or plus one on the short scale)?Long scale, as used in countries like Europe: continues:undecillion = (106)11 = 1066 1069 = 103 x (106)11 = undecilliard1072 = (106)12 = duodecillion1075 = 103 x (106)12 = duodecilliard1078 = (106)13 = tredecillion1081 = 103 x (106)13 = tredecilliardetcShort scale as used in countries like USA, continues:undecillion = (103)11+1 = 1036 1039 = (103)12+1 = duodecillion1042 = (103)13+1 = tredecillionetc

2351401 = (2*106) + (3*105) + (5*104) + (1*103) + (4*102) + (0*101) + (1*100)

There is an infinite number of possibilities: ... , 101+4.7, 102+3.7, 103+2.7, 104+1.7, 105+0.7, 106+(-0.3), 107+(-1.3), ... ..., 101.1+4.6, 102.1+3.6, ... ..., 101.15+4.55, ... etc. And all that is before bringing in irrational numbers.

20,965,304.405 = (2 x 107) + (0 x 106) + (9 x 105) + (6 x 104) + (5 x 103) + (3 x 102) + (0 x 101) + (4 x 100) + (4/101) + (0/102) + (5/103)

The 10 megabytes is equal to 10,000 kilobytes. There are 1,000 kilobytes in 1 megabyte. A kilo is 103, and a mega is 106. There are 103 kilos in a mega. As a kilo is 103, it might be easy to see that there are 103 x 103 in 106 (because 103 x 103 is 106). As there are 103 kilobytes in 1 megabyte, there are 10 x 103 kilobytes in 10 megabytes. That's 104 kilobytes in 10 megabytes, or 10,000 kilobytes in the 10 megabytes.

Not by itself. In the sequence 80, 82, 95, 100, 106... 95 is the median.

Not by itself. In the sequence 80, 85, 91, 99 106... 91 is the median.

20,965,304.405 = (2 x 107) + (0 x 106) + (9 x 105) + (6 x 104) + (5 x 103) + (3 x 102) + (0 x 101) + (4 x 100) + (4/101) + (0/102) + (5/103)

0.348619 = (0 x 100) + (3/101) + (4/102) + (8/103) + (6/104) + (1/105) + (9/106)

8.201165 = (8 x 100) + (2/101) + (0/102) + (1/103) + (1/104) + (6/105) + (5/106)

8.201165 = (8 x 100) + (2/101) + (0/102) + (1/103) + (1/104) + (6/105) + (5/106)

First order the numbers. 102 104 104 108 111 115 Since they are an even number of numbers, take the two middle numbers, add them together, and divide by 2. (104 + 108)/2= 106 Answer: 106

1, 2, 53, 106 1, 2, 103, 206

The simplest form of 106/206 is 53/103.

Your question was a little unclear in two ways: You said "using 3 digits". Are 1 and 2 digit numbers allowed? and If you reorder the numbers in a set, do you count it twice? For instance, if you had already counted the set 101, 102, 103, 104, 105, 106, would you also count 106, 105, 104, 103, 102, 101? If yes to both questions, there are 985,084,775,273,880,000 different sets. If yes to the first question, no to the second, there are 1,368,173,298,991,500 different sets. If no to the first question, yes to the second, there are 522,639,254,696,832,000 different sets. If no to both questions, there are 725,887,853,745,600 different sets. Hope this helped :).

answer:106 and other numbers

1,965,012 = (1 x 106) + (9 x 105) + (6 x 104) + (5 x 103) + (0 x 102) + (1 x 101) + (2 x 100)