The median of these fourteen numbers is 84.
By definition yes. The median is the number which is exactly in the middle of a set of numbers. The first quartile is the point where 25% of the numbers are to the left, and 75% of the numbers are to the right.
mean: 60 median: 56.5 mode: 56 range: [48,75]
78
For the set (87 81 75 75 75 70 62 62 62 62 62 56 56): The mean is 68.076923 repeating The median is 62 The mode is 62
If it is a small list of scores, like 6 of them, write them in a list, for example: 96, 87, 80, 79, 75, 75 Find the 'middle' which will occur BETWEEN two numbers 96, 87, 80 (middle) 79, 75, 75. Average the two numbers on either side of the 'middle.' In this example (80 + 79) / 2 = 79.5 If the list is larger find the middle by dividing the total number of cases by 2. In this example 6 / 2 = 3. The median will be the middle BETWEEN the 3rd and 4th score. (Average the 3rd and 4th score)
71 is the median of those numbers.
The median of the numbers 93 90 90 75 70 68 is 82.5.
There are 14 numbers - therefore, the median number is halfway between the seventh and eighth number. This is therefore 70.5.
Because there is an even number of numbers, it is the average of the two middle ones. (75 + 79)/2 = 77.
Range: 24 Median: 59.5 Mode: 57, 61, 58, 54, 68, 51, 65, 75
65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.
75*74*73*72*71*70*69*68/(8*7*6*5*4*3*2*1) = 16,871,053,725
Sort the numbers into numerical order:54, 68, 70, 72, 75, 76, 76, 76, 80, 88, 88, 88, 88, 92, 92, 93The median is the middle number which as there are 16 numbers is the mean of the middle two (highlighted above):median = (76 + 80) ÷ 2 = 78.
Since the set of data is arranged in numerical order, first we need to find the median (also called the second quartile), which separates the data into two equal groups, in our case there are 6 numbers in each group.54 65 66 68 73 75 | 75 78 82 82 87 97The first quartile (also called the lower quartile) is the middle value of numbers that are below the median, in our case is 67.54 65 66 | 68 73 75 | 75 78 82 82 87 97The third quartile (also called the upper quartile) is the middle value of numbers that are above the median, in our case is 82.54 65 66 | 68 73 75 | 75 78 82 | 82 87 97The interquartile range is the difference between the first and third quartiles, which is 15, (82 - 67).
Arrange the numbers in ascending order and pick out the middle number but sometimes the two middle numbers need to be added and divided by 2 if there are an even set of numbers. ____________________________________________________ The middle number (in a sorted list of numbers). To find the Median, place the numbers you are given in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. Put them in order: {10, 11, 13, 15, 16, 23, 26} The middle number is 15, so the median is 15. (If there are two middle numbers, you average them.) Accordingly: The median for: 94 83 78 70 66 68 75 53 54 is: 94, 83, 78, 75, 70, 68, 66, 54, 53 The median is : 70 The median for: 59 83 91 64 65 71 62 86 90 is: 91, 90, 86, 83, 71, 65, 64,, 62, 59 The median is 71
62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77 and 78.