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Q: What is the median of the numbers 81 97 99 89 91 76?

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28; when the numbers are arranged in order, the middle one is the median.

For median the list needs to be sorted into increasing order, but doing so also helps with the range and mode, so I'll do that first: {89, 76, 85, 76, 77, 84} → {76, 76, 77, 84, 85, 89} Mean: add them up and divide the sum by how many numbers there are: mean = (89 + 76 + 85 + 76 + 77 + 84) / 6 = 81 1/6 ≈ 81.167 Median: middle number when listed in order; if there are an even number of data items, then the median is the mean average of the middle two: There are 6 data items so median is mean average of middle two: median = (77 + 84) / 2 = 80 ½ = 80.5 Mode: the most frequent, it the number which occurs the most often. There can be more than one mode: mode = 76 as there are two of them and only 1 of all the other numbers. Range: the difference between the greatest and least numbers: range = 89 - 76 = 13

the median is 785

It is the middle value of: 12 16 28 76 and 89 which is 28

The mean of any set of numbers is the sum of those numbers divided by how many numbers there are. Here, the sum is 99+97+91+89+81+76=533. When you divide 533 by 6 (the total number of numbers), you get 88.83333... repeating forever. In mixed number form, this is 88 and 5/6.

Then that number will be the median. For example, if your set is 4, 4, 19, 20, 23, 23, 23, 43, 62, 76 and 89, then the second 23 is the middle number, and so it is the Median.

The median is (89 + 91)/2 = 90

Twelve numbers exactly are greater than 76 and less than 89.

The idea is to sort the numbers, and pick the number in the middle as the median. In cases like this, when you have two numbers in the middle (the size of the set is even), take the average of those two numbers.

They are: 83, 89 and 97

The numbers 83, 89 and 97 are prime.

It is 89.

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