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By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
y - 5x
5x plus 3 does equal 3 plus 5x; commutative law.
x + 3x + 5x is effectively a single term. A single term cannot have a greatest COMMON factor where the word common implies that it refers to two or more terms.
5x
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
y - 5x
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
5x plus 3 does equal 3 plus 5x; commutative law.
9 is the constant. 5 is the coefficient of the variable term. X is the variable term.
x + 3x + 5x is effectively a single term. A single term cannot have a greatest COMMON factor where the word common implies that it refers to two or more terms.
-10x + 5x = -5x
5x
You can do this by trying to find a pair of numbers that that have a sum which is equal to the coefficient of the middle term, and a product that is equal to the product of the coefficients of the first and last term. In other words, you want two numbers, "a" and "b" which add up to 5, and which have a product of -24: a + b = 5 a × b = -24 In this case, the numbers we need would be eight and negative three. We can then plug them into our equation, by splitting the middle term into the sum of those two numbers: x2 + 5x - 24 = x2 + 8x - 3x - 24 Now we can take pairs of those terms, and divide by common factors: = x(x + 8) - 3(x + 8) And finally, group like terms: = (x - 3)(x + 8)
x=6
It is: 5x
5x+5x-10 10x-10 is the only answer you can get from this