118 degrees
There are 540 interior degrees in a pentagon So: 540-112-102-118-107 = an angle of 101 degrees
Given rectangle ABCD with X as the midpoint of AB, we know that angles in a rectangle are right angles. Since CXD is given as 118 degrees, we can find angle ADX. Since angles around point X must sum to 360 degrees, we have ( \angle ADX = 180 - \angle CXD = 180 - 118 = 62 ) degrees. Consequently, since ( \angle XCD ) is supplementary to ( \angle ADX ), ( \angle XCD = 180 - 62 = 118 ) degrees.
Unless I'm missing something, I think the answer is 2. The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90 The factors of 118 are: 1, 2, 59, 118
It is: 118 = CXVIIICXVlll = 118
62
118 degree angle
118 DEGREE
Thise is the right answer ✅
118 degrees
It is the angle between the cutting edges.It is usually 118 degrees
It is an obtuse angle
118
Type your answer here... 118 DEGREE
There are 540 interior degrees in a pentagon So: 540-112-102-118-107 = an angle of 101 degrees
Suppose the angle is x. Then its complement is 90-x. So x = (90-x) + 28 = 118 - x So 2x = 118 and x = 59 (with complement 31).
Given rectangle ABCD with X as the midpoint of AB, we know that angles in a rectangle are right angles. Since CXD is given as 118 degrees, we can find angle ADX. Since angles around point X must sum to 360 degrees, we have ( \angle ADX = 180 - \angle CXD = 180 - 118 = 62 ) degrees. Consequently, since ( \angle XCD ) is supplementary to ( \angle ADX ), ( \angle XCD = 180 - 62 = 118 ) degrees.