There are 540 interior degrees in a pentagon
So: 540-112-102-118-107 = an angle of 101 degrees
A pentagon seems to fit the given description.
Right angles aren't formed by other angles - it is already an angle itself. However, if you bisect a right angle, it becomes two acute angles.
The opposite angles of a rhombus are congruent. So the angle opposite to the given angle is also 35 degrees. The consecutive angles of a rhombus are supplementary (add up to 180 degrees). So the supplement angle of the given angle is 145 degrees (180 - 35), and the angle opposite to that angle also will be 145 degrees.
All the angles of a square are 90 degrees.
They can be: acute, right angle, obtuse or reflex
For interior, the angle sum is 540 degrees, for exterior, the angle sum is 1260 degrees. * * * * * Partially correct! The sum of the exterior angles of any polygon is 360 degrees. The exterior angle is the supplement of the interior angle (180 - interior), NOT the reflex angle (360- interior). So the sum given 1260, which is based on the reflex angles is incorrect.
Remote interior angles
A pentagon seems to fit the given description.
180 minus two known angles = unknown angle
Right angles aren't formed by other angles - it is already an angle itself. However, if you bisect a right angle, it becomes two acute angles.
The opposite angles of a rhombus are congruent. So the angle opposite to the given angle is also 35 degrees. The consecutive angles of a rhombus are supplementary (add up to 180 degrees). So the supplement angle of the given angle is 145 degrees (180 - 35), and the angle opposite to that angle also will be 145 degrees.
All the angles of a square are 90 degrees.
They can be: acute, right angle, obtuse or reflex
The 'included side' is the side between the two given angles. The 'included angle' is the angle between the two given sides.
The sum of internal angles of a shape is given by the equation 180(n-2) where n is the number of sides. For a pentagon, which has 5 sides, this would be 180x3 = 540. The sum of external angles of a shape is given by (180-(x/n))n where n is the number of sides and x is the sum of internal angles. For a pentagon, this would be 5x(180-540/5) = 360
Complementary angles are those that add up to 90° Thus all angles complementary to a given angle must all be the same angle (90° - the_given_angle), ie they are all congruent angles.
No, it is not possible to have a pentagon with 2 obtuse angles and 3 acute angles. In a pentagon, the sum of all interior angles is always 540 degrees. If there are 2 obtuse angles (each greater than 90 degrees), the sum of these two angles alone would be more than 180 degrees, leaving insufficient room for the other three angles to be acute (less than 90 degrees).