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Mode = 2 = median
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What is the mean mode median and range of 1 2 1 8 9?
Mean: 4.2 Median: 2 Mode: 1 Range: 8
What is the median mode and range for 5 2 1 1 3 7 6?
Median: 3 Mode: 1 Range: 6
Write a c program to print mean median and mode?
#include<stdio.h> #define MAXVAL 1000 void sort1(int a[],int n); void median(int a[],int n); void mode(int a[],int n); int main() { int n; int arr[MAXVAL]; int i; printf("Enter the number of elements:"); scanf("%d",&n); printf("Enter the values:"); for(i=0;i<n;i++) { printf("a[%d]=",i); scanf("%d",&arr[i]); } sort1(arr,n); median(arr,n); mode(arr,n); } void sort1(int a[],int n) { int i; int j; int temp; for(i=0;i<n;i++) { for(j=i;j<n;j++) { if(a[i]>a[j]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } } } } void median(int a[],int n) { int median; int mid; if((n%2)==0) { mid=n/2; median=(a[mid-1]+a[mid])/2; } else { mid=(n+1)/2; median=a[mid-1]; } printf("The median is:%d\n",median); } void mode(int a[],int n) { int i; int count1[MAXVAL]; for(i=0;i<n;i++) { count1[i]=0; } for(i=0;i<n;i++) { count1[a[i]]++; } i--; int mode=count1[0]; int j; int k; int flag=0; for(j=0;j<=a[i];j++) { if(count1[j]>count1[mode]) mode=j; } for(j=0;j<=a[i];j++) { for(k=j+1;k<=a[i];k++) { if(count1[j]=count1[k] && count1[j]>count1[mode]) { flag=1; } } } if(flag==1) { printf("Mode cannot be calculated"); } else printf("the Mode is:%d",mode); }
What is the mean median mode and range of 9 and 9 and 8?
Mean: 4.2 Median: 2 Mode: 1 Range: 8
What is the mean median and mode for 3 4 2 1 1 6 8 1 1 3 2 2 10 12?
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1
What is the mean median and mode for 2 8 2 0 1 1 2 and 1?
Mean = 2.125 Median = 1.5 Mode = 1 and 2.
What is the mean mode median and range of 1 2 3 3 1?
mean= 2, mode= 1 and 3, median= 3, and range= 2
What is the mean mode median and range of 1 2 1 8 9?
Mean: 4.2 Median: 2 Mode: 1 Range: 8
What is the median mode and range for 5 2 1 1 3 7 6?
Median: 3 Mode: 1 Range: 6
Write a c program to print mean median and mode?
#include<stdio.h> #define MAXVAL 1000 void sort1(int a[],int n); void median(int a[],int n); void mode(int a[],int n); int main() { int n; int arr[MAXVAL]; int i; printf("Enter the number of elements:"); scanf("%d",&n); printf("Enter the values:"); for(i=0;i<n;i++) { printf("a[%d]=",i); scanf("%d",&arr[i]); } sort1(arr,n); median(arr,n); mode(arr,n); } void sort1(int a[],int n) { int i; int j; int temp; for(i=0;i<n;i++) { for(j=i;j<n;j++) { if(a[i]>a[j]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } } } } void median(int a[],int n) { int median; int mid; if((n%2)==0) { mid=n/2; median=(a[mid-1]+a[mid])/2; } else { mid=(n+1)/2; median=a[mid-1]; } printf("The median is:%d\n",median); } void mode(int a[],int n) { int i; int count1[MAXVAL]; for(i=0;i<n;i++) { count1[i]=0; } for(i=0;i<n;i++) { count1[a[i]]++; } i--; int mode=count1[0]; int j; int k; int flag=0; for(j=0;j<=a[i];j++) { if(count1[j]>count1[mode]) mode=j; } for(j=0;j<=a[i];j++) { for(k=j+1;k<=a[i];k++) { if(count1[j]=count1[k] && count1[j]>count1[mode]) { flag=1; } } } if(flag==1) { printf("Mode cannot be calculated"); } else printf("the Mode is:%d",mode); }
What is the mean median mode and range of 9 and 9 and 8?
Mean: 4.2 Median: 2 Mode: 1 Range: 8
What is the mean median and mode for 1 5 9 1 2 6 8 2?
The mean is 4.25, the median is 3.5 and the modes are 1 and 2.
Why is number 1 the median number of the numbers 1 0 4 1 1 4?
You are right. 1 is the median.The median of a set of data is found by arranging the data in increasing or decreasing order. So, we can arrange the items: 0, 1, 1, 1, 4, 4If the number of items of data is even, as it is in this case, then the median is the average (or mean) of the two middle numbers. So, the median is (1 + 1)/2 = 2/2 = 1If the number of items of data is odd, then the median is the middle number in the ordered set. For example the median of the data 1, 3, 3, 5, 6, 8, 9 is 5, because 5 is in the middle.It is also the mode. The mode of a set of data is the one item of data that occurs most often. 1 has the highest number of frequency in this sample. Thus 1 is the mode also.
What is the mean median and mode for 3 4 2 1 1 6 8 1 1 3 2 2 10 12?
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1
What are the steps for mean median and mode?
Mean = sum of observations/number of observations Median: Order the observations. Of there are an odd number of observations, the median is the middle one. So if there are n observations (where n is odd) then the median is the (n+1)/2 th observation. If n is even, the median is the average of the n/2 th observation and the (n/2 +1) th. Mode: Group the observations. The mode is the value or values that appear the most often. There may be no mode, a single mode or lots of them.
What is the mean median and mode of 3 4 5 5 2 7 1 8 and 9?
mode- 5 median- 5 mean- 4.8
What is the mean median and mode of 16 21 20 19 21 78 18 2 1 20?
Mean = 21.6 Median = 19.5 Mode = 20 and 21 ------------------------------------------------------------------------ If the "2 1" (between 18 and 20 at the end) is supposed to be "21" then Mean = 26 Median = 20 Mode = 20
