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Q: What is the mode and median of 1 2 0 5 8 2 9 2 7?

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Mean = 2.125 Median = 1.5 Mode = 1 and 2.

mean= 2, mode= 1 and 3, median= 3, and range= 2

Mean: 4.2 Median: 2 Mode: 1 Range: 8

Median: 3 Mode: 1 Range: 6

Mean: 4.2 Median: 2 Mode: 1 Range: 8

The mean is 4.25, the median is 3.5 and the modes are 1 and 2.

#include<stdio.h> #define MAXVAL 1000 void sort1(int a[],int n); void median(int a[],int n); void mode(int a[],int n); int main() { int n; int arr[MAXVAL]; int i; printf("Enter the number of elements:"); scanf("%d",&n); printf("Enter the values:"); for(i=0;i<n;i++) { printf("a[%d]=",i); scanf("%d",&arr[i]); } sort1(arr,n); median(arr,n); mode(arr,n); } void sort1(int a[],int n) { int i; int j; int temp; for(i=0;i<n;i++) { for(j=i;j<n;j++) { if(a[i]>a[j]) { temp=a[i]; a[i]=a[j]; a[j]=temp; } } } } void median(int a[],int n) { int median; int mid; if((n%2)==0) { mid=n/2; median=(a[mid-1]+a[mid])/2; } else { mid=(n+1)/2; median=a[mid-1]; } printf("The median is:%d\n",median); } void mode(int a[],int n) { int i; int count1[MAXVAL]; for(i=0;i<n;i++) { count1[i]=0; } for(i=0;i<n;i++) { count1[a[i]]++; } i--; int mode=count1[0]; int j; int k; int flag=0; for(j=0;j<=a[i];j++) { if(count1[j]>count1[mode]) mode=j; } for(j=0;j<=a[i];j++) { for(k=j+1;k<=a[i];k++) { if(count1[j]=count1[k] && count1[j]>count1[mode]) { flag=1; } } } if(flag==1) { printf("Mode cannot be calculated"); } else printf("the Mode is:%d",mode); }

Yes. For example, in the sequence {1,2,2,2,2,3,4,7} 2 is the median, and 2 is also the mode.

1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1

mode- 5 median- 5 mean- 4.8

(0+1)/2 = 0.5

2

Mean = sum of observations/number of observations Median: Order the observations. Of there are an odd number of observations, the median is the middle one. So if there are n observations (where n is odd) then the median is the (n+1)/2 th observation. If n is even, the median is the average of the n/2 th observation and the (n/2 +1) th. Mode: Group the observations. The mode is the value or values that appear the most often. There may be no mode, a single mode or lots of them.

Mean = 21.6 Median = 19.5 Mode = 20 and 21 ------------------------------------------------------------------------ If the "2 1" (between 18 and 20 at the end) is supposed to be "21" then Mean = 26 Median = 20 Mode = 20

Range: 7 Mean: 5.2 Median: 5 Mode: 2

You are right. 1 is the median.The median of a set of data is found by arranging the data in increasing or decreasing order. So, we can arrange the items: 0, 1, 1, 1, 4, 4If the number of items of data is even, as it is in this case, then the median is the average (or mean) of the two middle numbers. So, the median is (1 + 1)/2 = 2/2 = 1If the number of items of data is odd, then the median is the middle number in the ordered set. For example the median of the data 1, 3, 3, 5, 6, 8, 9 is 5, because 5 is in the middle.It is also the mode. The mode of a set of data is the one item of data that occurs most often. 1 has the highest number of frequency in this sample. Thus 1 is the mode also.

1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4

No, because the mode is the most common score, and does not necessarily represent the middle point of the scores, which is the median. For example: 1, 1, 1, 2, 3, 4, 5, 6, 7 In this set of data the mode is 1 but the median (the 5th score in this example) is 3.

Mean= 5,9,6,6,1,1,8,4 = (1,1,4,5,6,6,8,9)/8 = 5 Median= (5+6)/2 =5.5 Mode= 1 ans 6. Range= (9-1) = 8

Zero

What is the mode for 0 1 2 3 4 5 6 ?

yes it can. Imagine the set 1,1,1,1,1,1,1,1,1,1 well, the mode is obviously 1. there are ten 1s and 10*1/10=1 so the mean is one the median would be (1+1)/2=1 so the data has the same mean, medain and mode.

the median is the middle in a set of numbers so if you had a set of 5 numbers like -2, -1, 0, 1, and 2 the middle number would be zero.

They quick answer is YES!Here is an example.Before we begin let quickly recap what the we mean by "mean", "median", "mode" and "range":[MEAN] - The sum of all the values, divided by the total number of values.[MEDIAN] - The middle value when the data is arranged in numerical order.[MODE] - The most common value in a data set.[RANGE] - The difference between the highest and lowest values in the set.If we had the following numbers 1, 2, 2, 2, 3,The [MEAN] would be: TWO= 1+2+2+2+3/5 = 10/5 = (2)The [MEDIAN] would be: TWO= 1 2 (2) 2 3 = (2)The [MODE] would be: TWOThe most common value is (2)The [RANGE] would be: TWOrange = (highest - lowest) = (3-1) = (2)Therefore; Mean, Median, Mode and Range = (2)So the Mean, Median, Mode and Range can all be the same number![Answered by F:A:W:B:Y] - (As always, glad to help)

it is 3