9 and 12, since they both appear twice.
11 and 7 because they appear twice. (mode is how many times a number appears)
These are your 5 numbers: X X X X X the median (the middle number of a row) is 11, that means: X X 11 X X the mode (the most frequent number in a row) is 12, that means: X X 11 12 12 the mean (the average) is 10, that means: (X+X+11+12+12)/5=10 or: X+X+11+12+12=50 or: X+X=50-12-12-11 or: X+X=15 so the remaining numbers must be 15 combined, and lower then 11, that means they can be: 5 and 10 6 and 9 7 and 8 so you have 3 possible solutions: 5 10 11 12 12 6 9 11 12 12 7 8 11 12 12
The average is 10... 11+11+9+7+12=50... 50/5=10
The mean is the average. For example if you had the numbers 11, 10, 12, 11, 7, and 15. You would add them up and divide by how many numbers there are (which in this case is 6). The number you get is your mean (in this case the means in 11).The mode is the number that occurs most often. Using the same set of numbers above (11, 10, 12, 11, 7, and 15), the mode would be 11 because that's the only number that occurs the most. In other words, there is more than one of the same number.
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
mode
7, 10, 11, 12, 13, 14, 17
Mean: 7.44 Median: 7 Mode: 7 Range: 7
That set has no mode.
10 7 11 12 9 13 14 11 15 16 13 17 18 15 19 20...
4/5 = 0.8 5/7 ≈ 0.71 8/9 ≈ 0.89 10/12 ≈ 0.83 11/12 ≈ 0.92 Thus, the greater is 11/12. 11/12, 8/9, 10/12, 4/5, and 5/7.
(18 + 18 + 11 + 7 + 6 + 11 + 10 + 20 + 7)/9= 12========The mean, also often called the "average", is1/9 of (18 + 18 + 11 + 7 + 6 + 11 + 10 + 20 + 7)