the mode is 8 , because you have to subtract the biggest # with the smallest # = so ... 9-1 = 8 ... ya so ur answer is 8
* * * * *
That is the range - not the mode. The mode is the value that appears most often. So in this case each of the five numbers is a mode. The 5 numbers each appear once - more than the numbers that make no appearance at all.
Median: 3 Mode: 1 Range: 6
3
That set has no mode.
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
mode- 5 median- 5 mean- 4.8
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
The set of numbers is bimodal with modes 3 and 5.
That set has no mode.
2,4, and 5
Mean: 5 Median: 5 Mode: 3
Mean = 6 Mode = 5.
There is no mode. This sequence is not finding modes.