the mode is 8 , because you have to subtract the biggest # with the smallest # = so ... 9-1 = 8 ... ya so ur answer is 8
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That is the range - not the mode. The mode is the value that appears most often. So in this case each of the five numbers is a mode. The 5 numbers each appear once - more than the numbers that make no appearance at all.
Median: 3 Mode: 1 Range: 6
3
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
That set has no mode.
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
mode- 5 median- 5 mean- 4.8
The set of numbers is bimodal with modes 3 and 5.
That set has no mode.
2,4, and 5
There is no mode. This sequence is not finding modes.
Mean: 5 Median: 5 Mode: 3
1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4