6 occurs more than any other number, so it is the mode.
The mode is 6.
The mode is 4.
That set has no mode.
Mean= 5,9,6,6,1,1,8,4 = (1,1,4,5,6,6,8,9)/8 = 5 Median= (5+6)/2 =5.5 Mode= 1 ans 6. Range= (9-1) = 8
Mean: 7.875 Median: 7.5 Mode: 14, 6, 8, 1, 9, 5, 7, 13
That set has no mode.
The mode is 1.
There is no mode. This sequence is not finding modes.
Mean: 5 Median: 5.5 Mode: 6
0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11 mean = 6 and 3/11 median = 7 mode = 9
(1, 3, 3, 3, 5, 5, 6, 6, 8, 10)
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.