5
5, 6, 9, 10, & 10
That set has no mode.
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
There is no mode. This sequence is not finding modes.
7 Because 7 appears the most
14, 6, 8, 10, 9, 5, 7, 13 First re-arrange the terms into Rank Order. Hence 5,6,7,8,9,10,13,14. The MEDIAN is the Absolute middle term , which is (9+10) / 2 = 9.5 The MODE is is the most frequent term. As a;; terms occur with the same frequency of one. , then the Median is used as the Mode, Hence 9.5 again. THe MEAN is the sum of all the terms divided by the number of terms. Hence [5+6+7+8+9+10+13+14] / 8 => [72]/8 = 9 The means NB For good measure, the RANGE is 14 - 5 = 9 [
(1, 3, 3, 3, 5, 5, 6, 6, 8, 10)
3, 3, 5, 9, 10
9
none of the data repeat (they are all unique) so there is no mode.
There is no mode.
0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11 mean = 6 and 3/11 median = 7 mode = 9