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Q: What are 2 numbers have a sum of 25 and a product of 114?

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If the sum of 2 numbers is 25 and their product is 156, the numbers are 12 and 13.

If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.

13 + 6 = 19 19 + 6 = 25. 19 X 6 = 114.

The two numbers with a sum of 33 and a product of 200 are 25 and 8. 25 x 8 = 200, 25 + 8 = 33.

14 and 11

807

25 and 6.

Sum is 25, difference is 13 So twice the bigger is 25+13 = 38 ie bigger is 19 and twice the samller is 25-13 = 12 ie smaller is 6 So their product = 19*6 = 114

103

10 and 15

8 and 17

-5 and +5.

No two odd numbers can sum to 7.

5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10

12 and 13.

The numbers are: 25 and 10 because 25+10 = 35 and 25*10 = 250

25 + 3 = 28 25 x 3 = 75 The two numbers are therefore 25 and 3.

The sum of the first 25 prime numbers is 1,060.

Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25

It's unclear whether you want two numbers that add to a sum or multiply to a product. 25 x 4 = 100 25 + 75 = 100

25 and 3 25*3 = 75 25+3 = 28

The sum of the first 25 prime numbers is 1,060.

I guess you mean: what two numbers sum to 31 and multiply together to get 150? 6 & 25 (6 + 25 = 31, 6 x 25 = 150)

There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325

23 + 2 = 25