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C1V1 = C2V2

4 x .04 = 1 x V2

V2 = (4 x .04)/1

= 160mL

Therefore the volume of water that needs to be added is 120mL (minus the original volume).

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14y ago
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13y ago

4.0 (g/L) / 40 (g/mol NaOH) = 0.10 (mol/L NaOH) = 0.10 M

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Q: What is the molar concentration of a solution made by dissolving 4.0g of NaOH in enough water to make 1.0 L of solution?
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