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How many moles of SO2 can be produced from 67.1 moles of O2?
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many moles are present in 128 grams of sulphur dioxide?
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
What is the ratio of so2?
It is 1 atom of S to 2 of O.
How many moles are there in 2.56g of So2?
Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.
What is the molar mass of so2?
The molecular mass of sulfur dioxide is 64,07.
How many moles of SO2 can be produced from 67.1 moles of O2?
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Given the reaction 2 SO2 plus O2 --- 2 SO3 what is the molar ratio for O2 to SO3?
1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2
What mass of sulfur must be used to produce 12.6L of sulfur dioxide (SO2) at STP?
Assuming the equation for the reaction is S + O2 --> SO2, you first determine how many moles are in 12.6L of SO2: 12.6/22.4 = 0.56mol (22.4L = 1mol of any gas at STP.) The equation's molar ratio tells us that 0.56mol SO2 means 0.56mol S, because everything's in a 1:1 ratio. Now, consider sulfur's atomic mass of 32.1g/mol. 32.1x0.56 = approx. 18g sulfur. Now, if your sulfur is the S8 allotrope, you'll have to re-calculate for that.
How many moles are present in 128 grams of sulphur dioxide?
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
What is the ratio of so2?
It is 1 atom of S to 2 of O.
How many moles are there in 2.56g of So2?
Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.
Balance S8 02 -- SO2?
S8 + 8o2 --> 8so2
What is the molar ratio of hydrogen to oxygen?
In what compound??
What is the ratio between NaHCO3 and NaCl?
The molar mass of sodium chloride is 58,44 g. The molar mass of sodium bicarbonate is 84,007 g. The ratio is 1,437.
How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
