Q: What is the molar ratio of 02 to so2?

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Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.

Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2

It is 1 atom of S to 2 of O.

Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.

Related questions

The molecular mass of sulfur dioxide is 64,07.

Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.

1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2

Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2

Assuming the equation for the reaction is S + O2 --> SO2, you first determine how many moles are in 12.6L of SO2: 12.6/22.4 = 0.56mol (22.4L = 1mol of any gas at STP.) The equation's molar ratio tells us that 0.56mol SO2 means 0.56mol S, because everything's in a 1:1 ratio. Now, consider sulfur's atomic mass of 32.1g/mol. 32.1x0.56 = approx. 18g sulfur. Now, if your sulfur is the S8 allotrope, you'll have to re-calculate for that.

It is 1 atom of S to 2 of O.

Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.

S8 + 8o2 --> 8so2

In what compound??

The molar mass of sodium chloride is 58,44 g. The molar mass of sodium bicarbonate is 84,007 g. The ratio is 1,437.

The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.