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The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.

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What is the mass percent of oxygen on SO2?

The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.


Which is the greatest mass of SO2 that can produced from 15.0 mol Cu2S?

To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.


How many moles in 37.4g of SO2?

The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.


How many moles are in 3.82 g of SO2?

To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.


How many grams of sulfur must be burned to give 100.0 g of SO2?

To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.

Related Questions

What is the mass percent of oxygen on SO2?

The molar mass of SO2 is 64.07 g/mol. Oxygen has a molar mass of 16.00 g/mol. To calculate the mass percent of oxygen in SO2, we can divide the molar mass of oxygen (32.00 g) by the molar mass of SO2 (64.07 g) and multiply by 100 to get 50.05%.


Which is the greatest mass of SO2 that can produced from 15.0 mol Cu2S?

To find the maximum mass of SO2 produced from 15.0 mol of Cu2S, first determine the molar ratio between Cu2S and SO2. The balanced chemical equation shows that 4 mol of SO2 is produced for every 1 mol of Cu2S consumed. Thus, you would produce 60.0 mol of SO2 from 15.0 mol of Cu2S. Finally, convert the moles of SO2 to grams using the molar mass of SO2 to find the mass.


How many moles in 37.4g of SO2?

The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.


How many moles of SO2 is present in 0.45 grams of sulfur dioxide?

To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.


How many moles are in 3.82 g of SO2?

To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.


What is the molar mass of so2?

The molecular mass of sulfur dioxide is 64,07.


How many grams of sulfur must be burned to give 100.0 g of SO2?

To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.


How many moles of SO2 are present in 250.0 g?

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.


How many moles are there in 2.56g of So2?

Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.


What is the total mass in grams of 0.75 mole of SO2?

To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.


What is the mass percent of oxygen in SO2?

The molar mass of SO2 is 64.07 g/mol. Since oxygen has a molar mass of 16 g/mol and there are 2 oxygen atoms in SO2, the total mass of oxygen in SO2 is 32 g. Therefore, the mass percent of oxygen in SO2 is 32/64.07 * 100% = 50.05%.


The number of grams in 2.65 mol of So2 is 2.65?

To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.

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