Momentum=mass*velocity 0.5*4=2kgms-1
x=1/2at2 and a=9.81m/s2 so 2.88m = 4.905t2 t = 0.77 s v=at so v= 7.5 m/s momentum = mv = (m)kg* 7.5m/s = 7.5m Now with a mass of m/2 having a momentum of 7.5m we have to double the velocity. 7.5m = 7.5(m/2)*2 = 15m To get a velocity of 15m/s 15m/s = at so t= 1.53 s distance is x=1/2at2 x=1/2at2 x= 11.48m
240 ft
A falling stone will increase in speed until it reaches it's terminal velocity, the speed when the downward force of gravity equals the upward force of drag, which causes the net force on the stone to equal zero, thus achieving an acceleration of zero. If atmosphere is ignored, a falling body will accelerate at 32ft/s (9.75m/s). The distance traveled in the first second would be 16 feet (4.87m), in the second second: 48 feet (14.63m) and in the third second: 80 feet (24.38m); hence after three seconds an object would have fallen 144 feet (43.89 meters) and is traveling at 96ft/s (29.26m/s).
7% of 15 stone equals 1.05 stone.
17.5 stone or 17 stone 7 pounds
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