Cu2+ + I- --> Cu2I The compound created is Copper(I) Iodide
5050.05
That's the beginning of the Fibonacci series.
it is the associative property
Five is the coefficient of x.
Copper two
Cu2+ + I- --> Cu2I The compound created is Copper(I) Iodide
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
The name of Cu^2+ or (Cu2+) is called: "The name of Cu2+ is _________ ion or ________ ion" 1st blank is: copper(II) 2nd blank is: cupric It is correct. i am a teacher.
They have the same electron configuration as argon, which means they are isoelectronic with argon.
They have the same electron configuration as argon, which means they are isoelectronic with argon.
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
The octet rule does not apply to transition metals.
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.
Cu2+ + O2- + H+ + Cl- = Cu2+ + 2 Cl- + H2O
They have the same electron configuration as argon, which means they are isoelectronic with argon.
E2xoy4=cu8