They have the same electron configuration as argon, which means they are isoelectronic with argon.
They have the same electron configuration as argon, which means they are isoelectronic with argon.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.
Logoff their computers at the end of the work day
there ar about 200- 100 -_200
They have the same electron configuration as argon, which means they are isoelectronic with argon.
They have the same electron configuration as argon, which means they are isoelectronic with argon.
They all have the same electron configuration as the noble gas argon.
They have the same number of electrons. A neutral Ca atom would have 20 electrons but because it is a Ca2+ ion it only has 18 electrons (the same as Ar).
is electronic all have electronic config of {Ar} size Ca^2+^<k+<Cl-<s2-< IE S2-<CL-<K+<CA2+
calcium is normally [Ar] 4s2 if it is a 2+ ion, then it has lost 2 electrons so the configuration is just [Ar]
Yes, it is identical to Ar.
Not exactly as asked in the question. But K+, Ca2+ and Ar all have the same electronic configuration. All will have a total of 18 electrons.
Cl-, K+, Ca2+ all have [Ar] configuration with 18 electrons (1s2, 2s2 2p6, 3s2 3p6)
( a + ar ) = a ( 1 + r )
(Ar) Argon because Ca ion is Ca2+ so it give away 2 electrons
It forms a divalent cation, Ca2+, by losing two electrons and attains the electronic configuration of [Ar].