It means the logarithm to the base e. The number "e" is approximately 2.71828... In other words, if you ask, for instance, "what's the natural logarithm of 100", that's equivalent to asking "to what number must I raise 'e', to get the answer 100". The solution of the equation e^x = 100 in this example.
If you mean ln x it is 1/x
Derivative of natural log x = 1/x
d/dx lnx=1/x
The derivative of the natural log is 1/x, therefore the derivative is 1/cos(x). However, since the value of cos(x) is submitted within the natural log we must use the chain rule. Then, we multiply 1/cos(x) by the derivative of cos(x). We get the answer: -sin(x)/cos(x) which can be simplified into -tan(x).
the natural log, ln, is the inverse of the exponential. so you can take the natural log of both sides of the equation and you get... ln(e^(x))=ln(.4634) ln(e^(x))=x because ln and e are inverses so we are left with x = ln(.4634) x = -0.769165
logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999
Derivative of natural log x = 1/x
2 log(x)derivative form:d/dx(2 log(x)) = 2/x
You cannot.
log base 3 of x = lnx
Assuming you are asking about the natural logarithms (base e):log (-1) = i x pithereforelog (log -1) = log (i x pi) = log i + log pi = (pi/2)i + log pi which is approximately 1.14472989 + 1.57079633 i
log x = 0.127537
The derivative of a log is as follows: 1 divided by xlnb Where x is the number beside the log Where b is the base of the log and ln is just the natural log.
d/dx lnx=1/x
ln(x) = log10(X)/log10(e)
250x = 400000 then x log 250 = log 400000 so x = log 400000 / log 250 Natural logs could have been used instead of logs to base 10.
The derivative of the natural log is 1/x, therefore the derivative is 1/cos(x). However, since the value of cos(x) is submitted within the natural log we must use the chain rule. Then, we multiply 1/cos(x) by the derivative of cos(x). We get the answer: -sin(x)/cos(x) which can be simplified into -tan(x).
If: Ln(A) = X Then: A = ex