Do you mean "Why might a parallel line algorithm be needed?" or "What properties does a parallel line algorithm need to have?".
The cost optimal algorithm in parallel computing is the modular structured parallel algorithm that satisfy the insatiable demand of low power consumption, reduces speed and minimum silicon area.
You need to know what the graph points are.
It has two 5-tuples and 5 pairs of parallel lines. It need not have any line of symmetry.
PRAS: PARALLEL ALIGNMENT OF SEQUENCES It is an algorithm
Yes, two lines that lie in parallel to the same line are always parallel to each other. This is based on the Transitive Property of Parallel Lines, which states that if line A is parallel to line B, and line B is parallel to line C, then line A is parallel to line C. Thus, if two lines are both parallel to a third line, they must be parallel to each other.
Bresenhams' algorithm is better
Slope of the line and the coordinates of a point on the line [for example (-3,2)]
To determine an equation that represents a line parallel to a given line, you need to identify the slope of the original line. Lines that are parallel have the same slope but different y-intercepts. Therefore, if the equation of the original line is in slope-intercept form (y = mx + b), any line parallel to it will also be of the form (y = mx + c), where (c) is a different constant.
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
The cohen sutherland algo requires calculation of intersection of the line with the window edge.This direct calculation is avoided by performing a binary search for the intersection by always dividing the line at its midpoint.To implement it a parallel architecture is used and hardware division addition by 2 is very fast
Yes it's quite possible if need be.
[A Parallel line is a straight line, opposite to another, that do not intersect or meet.] Ie. Line 1 is Parallel to Line 2. ------------------------------------------------- <Line 1 ------------------------------------------------- <Line 2