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If you fit the following cubic t(n) = (-n3 + 9n2 - 20n + 18)/3 where n = 1, 2, 3, ... then the next number is t(6) = 1
There does not appear to be a missing number. The sequence is n2 + 1. 12 + 1 = 2 : 22 + 1 = 5 : 52 + 1 = 26 : 262 + 1 = 677. The next number in the sequence is 6772 + 1 = 458330.
16 is the next squared number.
12110 0r 1210
16 is the next number. All you do is sequentially add the next odd number. Therfore after 16 the next number would be 25... the next 36... the next 49... the next 54...
If you fit the following cubic t(n) = (-n3 + 9n2 - 20n + 18)/3 where n = 1, 2, 3, ... then the next number is t(6) = 1
The answer is 8 because 1+1=2, 1+2=3, 2+3=5,and 3+5=8.
There does not appear to be a missing number. The sequence is n2 + 1. 12 + 1 = 2 : 22 + 1 = 5 : 52 + 1 = 26 : 262 + 1 = 677. The next number in the sequence is 6772 + 1 = 458330.
1
The next number is 4, followed by -2
16 is the next squared number.
The number 0 and the next is 2.
1 + 1 = 2 2 * 2 = 4 4 - 1 = 3 3 + 3 = 6 6 + 2 = 8 8 - 1 = 7 so you just repeat that .. meaning that the next number is 15
4.
4
1+7=8 8-7=1 1+3=4 4+3=7 7-7=0 0+7=7 7-7=0 x=0+3 the next number is 3
12110 0r 1210