Looks Fibonacci, but you are missing the first 0... 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, etc. where each number is the sum of the preceeding two.
36, possibly. The sequnce being *2, *2, -6, *2, *2, -6 etc
Any number that you like! Given ANY number, it is easy to find a polynomial of order 4 that will generate the above four numbers and the selected fifth. The simplest rule using a polynomial of order 3 is Un = 33n3 - 192n2 + 353n - 192 for n = 1, 2, 3, ... Accordingly, the next number is 898.
The next number is 4, followed by -2
The next whole number after 1 is 2
1+1=2 : 1+2=3 : 2+3=5 : 3+5=8Therefore the next number is 8
let look at it and figure it out.. 1111 means the following first number on the right is the number of 2^0s which is 1 next number is the number of 2^1 powers or 2's next is the number of 2^2 =4s next is the number of 2^3=8 s So we have 1+2+4+8=15
The third number is 2 -- the first number is 1, second is 1, next is 1+1=2, then 1+2=3, 2+5=5 etc.
You add two then take one. 1+2=3, 3-1=2, 2+2=4, 4-1=3. The next number is 5.
The number 0 and the next is 2.
If you mean: 1, 2, 4, 8 and 16 then the next number is 32
4.
Correct. For example: 1 + 1 = 2 2 + 1 = 3 3 + 1 = 4