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It's the alphabet spaced by prime numbers: a+2=c, c+3=f, f+5=k, k+7=r, r+11 takes you past the end so start again at a = c.

Q: What is the next term in this sequence a 2 c 3 f 5 k 7 r?

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Each term in the sequence is three times the previous term plus two, so the next term is 485.1 (3 x 1 + 2) 5 (3 x 5 + 2) 17 (3 x 17 + 2) 53 (3 x 53 = 2) 161 (3 x 161 + 2) 485

3

The given sequence appears to have a common difference of 3. Thus, the next term in the sequence would be 17.

-1 deduct 3 each time

If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46

Related questions

15 since you multiply by 3 then subtract 3 in sequence

12 - 5(n-1)

The nth term is 5n-3 and so the next term will be 22

Each term in the sequence is three times the previous term plus two, so the next term is 485.1 (3 x 1 + 2) 5 (3 x 5 + 2) 17 (3 x 17 + 2) 53 (3 x 53 = 2) 161 (3 x 161 + 2) 485

The general term for the sequence 0, 1, 1, 2, 2, 3, 3 is infinite sequence.

The pattern is +2 /2 +3 /3 +4 /4, and the next term would be +5, or 8.

81

3

The given sequence appears to have a common difference of 3. Thus, the next term in the sequence would be 17.

-1 deduct 3 each time

The next term in the sequence (not the next sequence) is 76.It is obtained by using n= 6 int(n) = (29n4 - 338n3 + 1363n2 - 2158n + 1128)/24 for n = 1, 2, 3, etc

If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46