Study guides

☆☆

Q: What is the general term of the sequence 0 1 1 2 2 3 3.?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.

0, 1, 1, 2, 3, 5, 8 so the 7th term is 8

an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.

Every convergent sequence is Cauchy. Every Cauchy sequence in Rk is convergent, but this is not true in general, for example within S= {x:x€R, x>0} the Cauchy sequence (1/n) has no limit in s since 0 is not a member of S.

The nth term of the sequence is 2n + 1.

Related questions

If the first two numbers are 0, 1 or -1 (not both zero) then you get an alternating Fibonacci sequence.

Un = n*(n+1)/2

an = a1 + d(n - 1)

The Fibonacci sequence is a series of sums of two counting numbers and it starts with the lowest two, namely 0 and 1. Each successive number in the sequence is the sum of the two preceding it. Like this: The first term is usually 0 (although sometimes it is left out). The second term is 1. The third term is 1 + 0 = 1. The fourth term is 1 + 1 = 2. The fifth term is 1 + 2 = 3. The sixth term is 2 + 3 = 5. So the first 15 terms in the sequence would be: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, ... More formally, the Fibonacci sequence is defined recursively as: a1 = 0 a2 = 1 an+1 = an-1 + an There is also a general formula for the nth Fibonacci number: ( [1+sqrt(5)]n - [1-sqrt(5)]n ) / (2n * sqrt(5)) (where sqrt() means square root of)

This is an arithmetic progression. In general, If an A.P. has a first term 'a', and a common difference 'd' then the nth term is a + (n - 1)d. In the sequence shown in the question, the first term is 0 and the common difference is 5, therefore the nth term is, 0 + (n - 1)5. This can be rearranged to read : 5(n - 1) For example : the 7th term is 30 : 5(7 - 1) = 5 x 6 = 30.

In a Geometric Sequence each term is found by multiplying the previous term by a common ratio except the first term and the general rule is ar^(n-1) whereas a is the first term, r is the common ratio and (n-1) is term number minus 1

0, 1, 1, 2, 3, 5, 8 so the 7th term is 8

an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.

The general (or nth) term is given by the equation t(n) = a + (n-1)d where a is the first term and d is the common difference between successive terms.

A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.

-- Start with 0, 1 . -- Each term is then the sum of the two terms before it.

Every convergent sequence is Cauchy. Every Cauchy sequence in Rk is convergent, but this is not true in general, for example within S= {x:x€R, x>0} the Cauchy sequence (1/n) has no limit in s since 0 is not a member of S.

People also asked