If I understand the question correctly, the answer is 64.
7 x 8 = 56
56.
The number that both 7 and 8 can go into evenly is 56.
7 1/8 57/8 = 56/8 + 1/8 56/8 = 7 (because 7x8=56) :)
How about: 7*8 = 56
7 and 8 if you multiply them. 48 and 8 if you add them. 64 and 8 if you subtract them. 448 and 8 if you divide them.
To find out how many times 8 goes into 56, we divide 56 by 8. The division problem would be written as 56 ÷ 8. When we perform the division, we find that 8 goes into 56 exactly 7 times, with no remainder. Therefore, 8 goes into 56 seven times.
They are: 50+6 = 56 or 7*8 = 56
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
No, but 8 is the GCF of 56 and 72.
There are multiple possible two numbers whose LCM is 56: 1 & 56 2 & 56 4 & 56 7 & 8 7 & 56 8 & 14 8 & 28 8 & 56 14 & 56 28 & 56 56 & 56
"8 and 56 hundredths" refers to the decimal number 8.56. The "8" represents the whole number part, while "56 hundredths" indicates the decimal part, where "56" is in the hundredths place. This means there are 8 whole units and an additional 56 parts out of 100.