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There are an infinite number of numbers that are a multiple of 3 & 5 and have [exactly] 8 factors. The lowest is 30.

The next few are: 105, 135, 165, 195, 255, 285, 375, 435, ...

Any number of the form 15p where p is a Prime number (which is 2 or greater than 5) will be a multiple of 3 & 5 and have exactly 8 factors.

p=2 gives 15 x 2 = 30, p=7 gives 15 x 7 = 105, etc.

There are two further numbers (listed above): 135 (= 15 x 9) & 375 (= 15 x 25).

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Q: What is the number this is a multiple of five and three and has eight factors?
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Is 9 a factor of three?

No. 9 is a multiple of 3, an equal or larger number which is the product of factors.


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9 isn't prime, but one three-digit multiple of 18 is 108.


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24.


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What is the smallest positive integer N such that 2N is a perfect square 3N is a perfect cube and 5N is a perfect fifth?

For a number to be a perfect square, its prime factors must be separable into two identical sets. For a number to be a perfect cube, its prime factors must be separable into three identical sets. For a number to be a perfect 'fifth', its prime factors must be separable into five identical sets. ---- If N x 2 is separable into two identical sets of prime factors, then: * N must have an odd number of 2's in its prime factorisation. * All other prime factors of N must occur an even number of times. If N x 3 is separable into three identical sets of prime factors, then: * The prime factorisation of N must contain a number of 3's that is one less than a multiple of three. * All other prime factors of N must occur a number of times that is already a multiple of three. If N x 5 is separable into five identical sets of prime factors, then: * The prime factorisation of N must contain a number of 5's that is one less than a multiple of five. * All other prime factors of N must occur a number of times that is already a multiple of five. ---- From the above, we know that N's prime factorisation must contain 2's, 3's and 5's. How many times does 2 appear in the prime factorisation of N? - It must be an odd number. - It must be a multiple of three. - It must be a multiple of five. The smallest valid frequency is 15. How many times does 3 appear in the prime factorisation of N? - It must be an even number. - It must be one less than a multiple of three. - It must be a multiple of five. The smallest valid frequency is 20. How many times does 5 appear in the prime factorisation of N? - It must be an even number. - It must be a multiple of three. - It must be one less than a multiple of five. The smallest valid frequency is 24. ---- Therefore N = 215 x 320 x 524 = 6810125783203125000000000000000. That seems to be the smallest possible value.

Related questions

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