It is 3.
9
It is a 3. Look at the ones digit of successive powers of 7; this need only be done by considering the multiplication of the ones digit of the previous power of 7 by 7 (as this is the only calculation that affects the ones digit as each successive power of 7 is the previous power multiplied by 7) and taking the result modulus 10 (to extract the new ones digit as any excess over 9 is carried into the tens column): 7¹ → 7 mod 10 = 7 7² → (7×7) mod 10 = 9 7³ → (9×7) mod 10 = 3 7⁴ → (3×7) mod 10 = 1 7⁵ → (1×7) mod 10 = 7 At this point the pattern of the ones digit will obviously repeat the sequence of the four digits {7, 9, 3, 1}. To find the ones digit of any power of 7, take that power modulus 4 use that digit from the four digit sequence. Note that when taking the number modulus 4, the result will be in the range 0-3; when the result is 0, use the 4th digit from the sequence. 2015 mod 4 = 3 → the third digit of {7, 9, 3, 1}, which is 3, will be the ones digit of 7²⁰¹⁵.
Seven to the 100 power equals 700. In the ones place there would be the number zero.
The value of the ones digit in 27 is 7.
It is the digit 7 that is in the ones or units place
The digit in the ones place is 7.
It represents 7 units.
7 ones
ones
Seven ones
71 = 7 72= 49 73 = 343 74 = 2401 75 = 16807 76 = 117649 The last two digits cycle after each exponent multiple of 4. As 2011 = (4 x 502) + 3, then the tens digit in 72011 is the same as the tens digit in 73.......which is 4.
The digit in the ones place of the number 127.869 is 7. The ones place is the integer part of the number immediately to the left of the decimal point. In this case, the number before the decimal is 127, and the last digit of this integer portion is 7.