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1. 9x = 53 - 4y

2. 3y = 26 - 4x

If we multiply 1. by 3 we get:

3. 27x = 159 - 12y

If we re-order 2. to 4x = -3y + 26 and then multiply by 4 we get:

4. 16x = -12y + 104

If we now subtract 4. from 3. we get:

5. 11x = 55

Thus x = 55/11 = 5

Substituting x = 5 back into 1. gives:

45 = 53 - 4y

Thus

4y = 53 - 45

4y = 8

y = 8/4 = 2

Therfore our ordered pair written in the form (x, y) is (5, 2).

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Q: What is the ordered pair for 9x equals 53-4y and 3y equals 26-4x?
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