+4
+6, because the oxidation number of oxygen is -2x3=-6
The oxidation of K2S2O3 is 2K2S2O3 → 2K2SO4 + S + SO2.
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
The oxidation state is +3.
This chemical equation is:2 ZnS + 3 O2 = 2 ZnO + SO2
The oxidation number of Al is +3.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The oxidation state of Boron in BO3^-3 is +3. This is because the overall charge of the ion is -3, and each oxygen atom has an oxidation state of -2. Hence, the Boron atom must have an oxidation state of +3 to balance the charges.
The oxidation number of H in HNO2 is +1, the oxidation number of N is +3, and the oxidation number of O is -2.
In this case you have a Salt that comes from a binarius acid (HCl) you have to remember in salts you are always using the oxidation number with H (Cl= -1) so Cr is using 3 :) as you have seen im not a English native speaker... sorry for mistakes :D
Oxidation number of N is +3. Oxidation number of H is -1.