2400, 300, 80 and 10
2400, 300, 80 and 10
2400, 300, 80 and 10
540 and 18
To find the partial products of 62 x 45, we can break it down into simpler components. First, we multiply 60 (from 62) by 40 (from 45) to get 2400. Then, we multiply 60 by 5 to get 300, and finally, we multiply 2 (from 62) by 40 to get 80, and 2 by 5 to get 10. Adding these partial products together: 2400 + 300 + 80 + 10 gives us a total of 2790.
To find the partial products for 62 x 45, you can break down the numbers into their place values. First, calculate 62 x 40 (which is 2480) and then 62 x 5 (which is 310). Adding these two partial products together gives you 2480 + 310 = 2790, which is the final result.
45
To use the partial products algorithm for 58 x 62, first break down the numbers into tens and units: 58 can be split into 50 and 8, while 62 can be split into 60 and 2. Next, calculate the products of each combination: 50 x 60 = 3000, 50 x 2 = 100, 8 x 60 = 480, and 8 x 2 = 16. Finally, add these partial products together: 3000 + 100 + 480 + 16 = 3596. Thus, 58 x 62 = 3596.
(2+45)×83×62×4×3×2×2+(297−37) = 11,609,636
107
62 + 12 + 45 = 119
9 goes into 62 only six times with a remainder of 8.
540 + 18