There are infinitely many possible answers. The simplest cubic polynomial is
Un = (2n3 - 11n2 + 27n - 14)/2 for n = 1, 2, 3, 4.
The difference doubles each time. 2+3=5.. 5+6=11.. 11+12=23..Therefore the next number in the sequence would be 47, since 23+24 = 47.
6y + 11 = 23 6y = 23 - 11 6y = 12 y = 12/6 y = 2.
It is: 3 6 12 24 48 .... double up each time
If you mean: 2 5 11 23 47 then they are increasing by 3 6 12 24
The answer is 47 The first term has 3 added to it = 2 + 3 =5 The second term has 6 added to it = 5 + (3 x 2) =5 + 6 = 11 The 3rd term is = 11 + (6 x 2) = 11 + 12= 23 Hence the next one is = 23 + (12 x 2) = 23 + 24 = 47
23/6 - 15/2 = 23/6 - 45/6 = -22/6 = -11/3
2, 4, 11 and 22
The pattern is this: The number before, plus itself plus 2. For example: 1 (number)+ 0 (number berfore)+ 2 (always use a two in this pattern) = 3 then 1+3+2=6 then 3+6+2+11 and 6+11+2=19, which is your pattern. So the answer is 11+19+2=32. Now the pattern is 1,3,6,11,19,32 Thats a wrap.
(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12(5/6) * (1/10) + (2/3) / (4/11) = (5/6) * (1/10) + (2/3) * (11/4)= (1/12) + (11/6) = 1/12 + 22/12 = 23/12 or 111/12
The factor pairs of 66 are: 1 × 66 2 × 33 3 × 22 6 × 11
(23/4)/x = 11/2 (11/4)/x = 3/2 or 1/x = (3/2)*(4/11) = 6/11 x = 11/6 That is, 11/6 of two and three quarters is one and a half.
2 ,5, 11, 23, 47, 95 ....... Double up each time: 3, 6, 12, 24, 48 ........