There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" pattern. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one. One possible soultion, based on a polynomial of order 4 is:T(n) = (-2*n^4 + 27*n^3 - 121*n^2 + 234*n - 126)/6 for n = 1, 2, 3, ...
(7+11)/2 + 15 = 24 7+11 = 18/2 = 9 + 15 = 24
15 + 7/1 + 2 = 15 + 7 + 2 = 24
-7 x -2= 14 24 - 9= 15 So no, it is not equal.
2(24 + 7) = (2 x 24) + 2 x 7) = 2 x 31 = 62
The pattern will be +2, +3, +4, +4
It is: (15-7)*(12-9) = 24
5/8 + 7/12 = 15/24 + 14/24 = 29/24 = 1 and 5/24.
(57-42) (24-23) = 15 x 1 = 15. See discussion page.
10-2=8-1=7*2=14+1=15-2=13-1=12*2=24+1=25 Therefore, subtract 2 and get 23.23, 22, 44, 45. The pattern is minus 2, minus 1, times 2, plus 1, repeat.
2 7/24:= [(24*2)+7/24= [48+7]/24= 55/24 in improper fractionAnswer:The reciprocal of 2 7/24 is the reciprocal of 55/24 which is 24/55.
-8 plus 15 = 7
1 1/2 or 3/2, any fraction equivalent to 3/2 or 1 1/2 (such as 24/16 or 1 7/14).