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Q: What is the percent 59.7 lithium mass of 100 g of the compound?
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What is the formula for the percent by mass of a compound?

((mass of element)/(mass of compound))*100


If lithium carbonate contains 18.8 percent lithium. What mass of lithium is present in a 1.55g of lithium carbonate?

To work out the mass of one element within a compound (ie the mass of Lithium in Lithium Carbonate), first work out the RFM (Relative Formula Mass) of the compound. To do this, look on the periodic table (PT) & add up the RAM (Relative Atomic Mass) of all of the atoms in the compound (the RAM is the larger of the 2 numbers in each box on the PT). So, if the formula for one molecule of Lithium Carbonate is Li2CO3, then the RFM is Li + Li + C + O + O + O = 7 + 7 + 12 + 16 + 16 + 16 = 74 Next work out what percentage of the compound is the element you want to know. So, Lithium accounts for 14 (2 Lithiums = 7 x 2) out of every 74 grams of Lithium Carbonate. As a percentage, this is ( 14 / 74 ) x 100 = 18.9 %. So, 18.9% of 1.55g [ ( 1.55 / 100 ) x 18.9 ] = 0.29g So there is 0.29g of Lithium is 1.55g of Lithium Carbonate.


How find percent compsotion of oxygen in Na2O?

To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.


What is the formula for mass percent?

mass % of element X = mass of element X ____________________ X 100 total mass of compound or mass of solute _____________________________ X 100 mass of solute + mass of solvent


Lithium has only two naturally occurring isotopes The mass of lithium-6 is 6.01512 amu and the mass of lithium-7 is 7.01601 amu Use the atomic mass of lithium to calculate abundances mass Li 6.941?

The atomic mass of Lithium is equal to the weighted average of the two naturally occurring isotopes. Let M=the atomc mass of Lithium; M1=the mass of lithium-6;M2=the mass of Lithium-7; %a=the abundance of lithium-6; %b=the abundance of lithium-7. M=(M1*%a+M2*%b)/100 we know that %a and %b must add up to give us 100%, so %a=100-%b. Therefore M=(M1*(100-%b)+M2*%b)/100 Then we just need to solve for %b because everything else is known. M=(M1*100-M1*%b+M2*%b)/100-->M-M1=(-M1*%b+M2*%b)/100 100(M-M1)=(-M1*%b+M2*%b)-->%b=100(M-M1)/(M2-M1)=92.5% Then %a=100-%b=100-92.5=7.5%


How is the percent composition by mass determined?

For a chemical compound, ex. ABC: Percent (%) of A is (atomic weight of A x 100)/molecular weight of ABC.


How is percent composition by mass determined?

For a chemical compound, ex. ABC: Percent (%) of A is (atomic weight of A x 100)/molecular weight of ABC.


Percent age of nitrogen in urea and ammonia?

it can be calculated using the formula percentage composition of N =Gram molecular mass of nitrogen in the compound/ Gram molecular mass of compound *100


What is the percent composition of O in LiOH?

The formula shows that oxygen is one atom out three in the formula unit, so that the atomic percent of oxygen in the compound is 33.333.......... By adding the gram atomic masses of the three elements, one obtains 23.95 as the gram formula mass, to the justified number of significant digits (the four digits in the value for the gram atomic mass of lithium), and 100 (15.9994/23.95) is 66.80 percent by mass of oxygen in LiOH.


What is the percent composition of oxygen in lithium hydroxide?

The molar mass of LiOH is 24,01874. The atomic weight of oxygen is 15,9994.24,01874 g----------------100 %15,9994 g---------------------xx = 15,9994 . 1oo/24,01874 = 66 %


What is the equation to find the percentage by mass of an element if the total mass of the compound and the mass contribution of the element are known?

Amount of mass of component Y divided by total mass times 100% equals (=) percent (%) Y component.


What is the gram mass of compound if 5 moles of the compound has a mass of 100 grams?

The molar mass is 20 g.