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What is the percent area cleaned by the wiper if the 180 degree rotational wiper diameter D is equal to the length of the solar panel D equals 156Cm and Breath of solar panel equals 78Cm?
Wiki User
∙ 12y ago
Area covered by the wiper is that of a semi-circle with diameter D, or the length of the solar panel - 156 cm.
So the area = (1/2)*(PI/4)*(D2) = (1/2)*(PI/4)*(156cm2) = 9556.72 cm2
Now find the area of the solar panel: area = length*width = 156 cm * 78 cm = 12,168 cm2
Now % area cleaned will be the area of the wiper / area of the panel:
9556.72 cm2 / 12168 cm2 * 100% = 78.5%
Wiki User
∙ 12y ago
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