100*80/100 = 80%
80%
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
(work out/work in) x 100
Efficiency as a percent is output/input * 100%12000/15000 * 100% = 80% efficiency which makes sense, because it takes more work (input) than it give out (output). So the efficiency should be less than 100%.
A system that is 35 percent efficient converts 35 percent of the input energy into useful work or output, while the remaining 65 percent is lost, often as waste heat or through other inefficiencies. For instance, in an engine, if it burns fuel to produce power, a 35 percent efficiency means that only 35 percent of the fuel's energy is effectively used for propulsion, with the rest wasted. This efficiency rating helps gauge performance and indicates potential areas for improvement.
50
80%
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
(work out/work in) x 100
Work done = (force * distance)>Efficiency (%) = (Work done output / Work done input) * 100
The mechanical efficiency of this machine is 30 percent.
No, a simple machine with less output work than input work is said to have less than 100 percent efficiency. Efficiency is a measure of how well a machine converts input work into output work, with 100 percent efficiency meaning that all input work is converted to useful output work.
To find the work out, you can use the formula for efficiency: Efficiency = (Work out / Work in) * 100. Given that the efficiency is 95%, you can rearrange the formula to find Work out as follows: Work out = (Efficiency / 100) * Work in. Substituting the values, you get Work out = (0.95) * 95 J = 90.25 J.
The formula for the percent efficiency of a pulley is (output work/input work) x 100%. It compares the output work (work done by the pulley) to the input work (work done on the pulley) to determine how efficient the pulley system is in transferring energy.
That's the machine's "efficiency".
When the efficiency of a simple machine is 85 percent, it means that 85 percent of the input work is converted into useful output work, while the remaining 15 percent is lost due to factors like friction and heat. This efficiency percentage gives an idea of how effectively the machine is performing its intended task.
Since the work output is less than the work input, there is a loss of energy during the process. The efficiency of the system can be calculated by taking the ratio of the work output to the work input, which in this case is 80 j / 100 j = 0.8 or 80%. This means that 80% of the input energy was successfully transferred to move the box up the inclined plane.