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What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution?
Wiki User
∙ 10y ago
13,75 % NaCl
Wiki User
∙ 10y ago
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What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
What is the molar mass of haemocyanin and the freezing point of the solution when an aqueous solution is prepared by dissolving 1.5 grams of haemocyanin a protein obtained from crabs in 0.25 litres of?
Haemocyanins are a group of proteins.
What will be the molarity for a solution prepared by dissolving a 10 grams compound with a molecular mass of 100 in 1 L of water?
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
What volume of a 150 M solution can be made by dissolving 18.0 grams of sodium hydroxide?
Check the spelling: 150 M ?
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
What is the mass percent of a solution prepared by dissolving 18.9 grams of solid into 39.5 grams of water?
32.4
What is the percentage concentration of a solution prepared by dissolving 5.48 grams of silver nitrate in 25.0 grams of water?
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
What percentage is a solution that contains 9 grams of sodium chloride?
That depends on how much solvent you are dissolving the 9 grams of salt in.
What is the molar mass of haemocyanin and the freezing point of the solution when an aqueous solution is prepared by dissolving 1.5 grams of haemocyanin a protein obtained from crabs in 0.25 litres of?
Haemocyanins are a group of proteins.
What does 5wt mean in oil weights?
This is the number of grams of solute in 100 grams of solution. As an example, a 5%w/w solution in water is prepared by dissolving 5 grams of solute in water and then adding further water with mixing until the final weight is 100 gram.
What will be the molarity for a solution prepared by dissolving a 10 grams compound with a molecular mass of 100 in 1 L of water?
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
What is meant by the mass mass percent concentration of a solution?
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
How do you make BaCl2 solution?
by dissolving the amount you want in mole or grams in one dm3 of water
What is the formula of mass percentage?
grams solute ------------------ x 100 grams solution
What is the molarity of a solution prepared by dissolving 1.56 grams of gaseous HCl in enough water to make 26.8 mL of solution?
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
