How about 7*7 = 49 because 4+9 = 13
No. Think 13, 22, 31 for a start!
The sum of the digits in '89' is 17, so I don't need toworry about any perfect square bigger than 16.1: 104: 13, 22, 31, 409: 18, 27, 36, 45, 54, 63, 72, 8116: 79That's 14 of them .
I did it by trial and error. 7^2 is 49. 4 + 9 = 13
13
Start with the smallest multiple of 13 and continue with the next smallest until finding one that fits the specifications. 13, sum of digits is 1 + 3 = 4 which is not prime 26, sum of digits is 2 + 6 = 8 which is not prime 39, sum of digits is 3 + 9 = 12 which is not prime 52, sum of digits is 5 + 2 = 7 which is prime So, 52 is the smallest positive multiple of 13 for which the sum of its digits is prime.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
13
Numbers whose digits add to a perfect square between 10 and 87 are: 10 = 1 + 0 = 1 = 12 13 = 1 + 3 = 4 = 22 18 = 1 + 8 = 9 = 32 22 = 2 + 2 = 4 = 22 27 = 2 + 7 = 9 = 32 31 = 3 + 1 = 4 = 22 36 = 3 + 6 = 9 = 32 40 = 4 + 0 = 4 = 22 45 = 4 + 5 = 9 = 32 54 = 5 + 4 = 9 = 32 63 = 6 + 3 = 9 = 32 72 = 7 + 2 = 9 = 32 81 = 8 + 1 = 9 = 32 This is a total of 13 numbers.* * * * *And also79 = 7 + 9 = 16 = 42So a total of 14 numbers.
65
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
65
1 and 12