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306 inches (6 sides x 51 = 306).

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11y ago

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What is the perimeter of a right triangle if the hypotenuse is 51 inches and one leg is 24 inches?

Using Pythagoras' theorem the other leg is 45 inches So: 51+24+45 = 120 Perimeter = 120 inches


What is the length of each side of a square whose perimeter is 51 meters?

The perimeter of a square is calculated by the formula ( P = 4s ), where ( s ) is the length of one side. Given that the perimeter is 51 meters, you can find the length of each side by dividing the perimeter by 4: ( s = \frac{51}{4} = 12.75 ) meters. Therefore, each side of the square is 12.75 meters long.


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How many 1x4 are needed too wrap a 22 inch octagon 34 inches tall?

To determine how many 1x4 boards are needed to wrap a 22-inch octagon that is 34 inches tall, first calculate the perimeter of the octagon. The perimeter is 22 inches multiplied by 8 sides, totaling 176 inches. To find out how many 1x4 boards (which are typically 3.5 inches wide) are required, divide the total perimeter (176 inches) by the width of one board (3.5 inches), which equals approximately 50.29. Therefore, you would need 51 boards to wrap the octagon.


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