A rectangle measuring 12 inches by 8 inches has a perimeter of 40 inches, since 12 + 12 + 8 + 8 = 40 inches.
Perimeter = 100 inches Area = 600 square inches
Length and side: 7 inches and 5 inches respectively
It is 2*(9+5) = 2*14 = 28 inches.
7 by 5 inches would satisfy both the perimeter and the area.
Typically a Frame will have about 1/4 of an inch to play with on the inside dimension so that would make the inside dimensions 5 1/4 x 7 1/4. if your frame is 3 inches you need to double it to make it 6 inches (3 inches for top + 3 inches for bottom = 6 inches for the top and bottom dimensions.) so your final size would be 11 1/4 x 13 1/4
Perimeter = 100 inches Area = 600 square inches
Length and side: 7 inches and 5 inches respectively
It is 2*(9+5) = 2*14 = 28 inches.
perimeter is the sum of all side lengths. Since a 9 by 11 has 2 sides 9 inch and 2 sides 11 inch, perimeter is 9+9+11+11 = 40 inches
48
7 by 5 inches would satisfy both the perimeter and the area.
The perimeter is 2 times the length plus 2 times the width.
17.5 inches
Typically a Frame will have about 1/4 of an inch to play with on the inside dimension so that would make the inside dimensions 5 1/4 x 7 1/4. if your frame is 3 inches you need to double it to make it 6 inches (3 inches for top + 3 inches for bottom = 6 inches for the top and bottom dimensions.) so your final size would be 11 1/4 x 13 1/4
It is: 9+11+9+11 = 40 inches
Perimeter, since it measures the distance around a shape. Area measures the interior. Or, more specifically, height by width, for example, 8x10 or 11x14 (inches). The perimeter for an 8x10 would be 2 times 8 plus 2 times 10, or 36 inches, but that would be insufficient to differentate an 8x10 frame from, say, a 6x12 frame (admittedly a rare size, but still possible.) So, while the common specification of a frame by height and width could be reduced to either perimeter or area, it is never done that way, precisely because important information is lost, the actual usable size of the frame.
52"