Q: What is the perimeter of a rectangle 24 cm long and 10 cm wide?

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That is not a square, it is a rectangle and it has a perimeter of 36 inches.

The perimeter is: 1+10+1+10 = 22 cm

28 cm

12 x 2 + 10 x 2= 44

_______10________ |_______________ | 3_______________ 3 |_______10_______| 3+3+10+10= 26 yds

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That is not a square, it is a rectangle and it has a perimeter of 36 inches.

The perimeter is: 1+10+1+10 = 22 cm

28 cm

10*2+5*2 = 30 CM

12 x 2 + 10 x 2= 44

5x2= 10 8x2=16 10+16=26 perimeter= 26!

_______10________ |_______________ | 3_______________ 3 |_______10_______| 3+3+10+10= 26 yds

Further information is needed to provide an answer to this question. If the area is 140 sq units, then this could be formed from a rectangle 1 unit wide by 140 units long - giving a perimeter of 2 x 140 + 2 x 1 = 282 units. But, the rectangle could be 14 units wide and 10 units long giving a perimeter of 2 x 14 + 2 x 10 = 48 units.

The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm

I don't know what you're asking, so I'll list both the area and perimeter Perimeter: 10+6+10+6 = 32 inches Area: 10*6 = 60 inches

The area doesn't tell you the perimeter.-- If the square mile is inside a circle, then the perimeter (circumference) is 3.545 miles.-- If the square mile is inside a square, then the perimeter is 4.000 miles.-- If the square mile is inside rectangle that's 2 miles long and 1/2 mile wide,then the perimeter is 5.000 miles.-- If the square mile is inside a rectangle that's 10 miles long and 0.1 mile wide,then the perimeter is 20.2 miles...etc.The area doesn't tell you the perimeter.

This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.