That is not a square, it is a rectangle and it has a perimeter of 36 inches.
The perimeter is: 1+10+1+10 = 22 cm
28 cm
2 x (24 + 10)...68cm
12 x 2 + 10 x 2= 44
That is not a square, it is a rectangle and it has a perimeter of 36 inches.
The perimeter is: 1+10+1+10 = 22 cm
28 cm
2 x (24 + 10)...68cm
Well, honey, the perimeter of a rectangle is calculated by adding up all the sides, so for your 23cm long and 10cm wide rectangle, you just add up all the sides: 23 + 23 + 10 + 10 = 66cm. Voilà, you've got yourself a perimeter!
10*2+5*2 = 30 CM
12 x 2 + 10 x 2= 44
5x2= 10 8x2=16 10+16=26 perimeter= 26!
The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the room is 12 feet long and 10 feet wide. To find the perimeter, you add the length of all sides: 12 + 12 + 10 + 10 = 44 feet. Therefore, the perimeter of the room is 44 feet.
Further information is needed to provide an answer to this question. If the area is 140 sq units, then this could be formed from a rectangle 1 unit wide by 140 units long - giving a perimeter of 2 x 140 + 2 x 1 = 282 units. But, the rectangle could be 14 units wide and 10 units long giving a perimeter of 2 x 14 + 2 x 10 = 48 units.
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
I don't know what you're asking, so I'll list both the area and perimeter Perimeter: 10+6+10+6 = 32 inches Area: 10*6 = 60 inches