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What is the perimeter of a rectangle that is 1 and one third inches long and 3 and one half inches wide?
First, you could find the common denominator of the fractions, which is 6, and change all of them (the fractions) to sixths...giving you 1 2/6 + 3 3/6 + 1 2/6 + 3 3/6 which equals to 8 10/6 or 8 + 1 4/6 which is 9 2/3...OR you could simply add 3 1/2 + 3 1/2, giving you 7, and then add 1 1/3 + 1 1/3, giving you 2 2/3, add those two numbers together, 7 + 2 2/3 and your answer is still: 9 2/3 inches!
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The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
The perimeter of a rectangle is 200 inches the length exceeds the width by 96 inches?
Length + width = half perimeter = 100". Length is 98", width is 2"
The perimeter of a rectangle is 218 inches The length exceeds the width by 87 inches Find the length?
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
What is the perimeter and area of a rectangle that has a length of 12 inches and a width of 10 and a half inches?
Perimeter = 2*(L + W) = 2*(12 + 10.5) = 2*22.5 = 45 inches. Area = 12*10.5 = 126 square inches.
The perimeter of a rectangle is 152 inches The length exceeds the width by 36 inches What is the length and width?
Do-it-in-your-head method:Length + width is half the perimeter, ie 76 inches;76 - 36 = 40;Half of 40 is 20: this is the width;20 + 36 = 56: this is the length.Job done.
If the height of a rectangle is eight and three fourths the perimeter is thirty eight and a half what is the area?
The perimeter of that rectangle is 89.6875.
When you fold a square paper vertically the new rectangle has a perimeter of 39 inches what is the original area of the square?
When a square paper is folded vertically to form a rectangle with a perimeter of 39 inches, the length of the rectangle is 19.5 inches (half of the perimeter). Since the length of the rectangle is the same as the side length of the original square, the area of the original square can be calculated as the square of the side length, which is 19.5 inches squared, equaling 380.25 square inches.
The perimeter of a rectangle is 24 inches. And its length is 3 times its width. What are the length and the width of the rectangle?
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
What is the perimeter of a square with a side measuring eleven and a half inches?
What is the perimeter of a square with a side measuring eleven and a half inches?
The perimeter of a rectangle is 232 inches The length exceeds it by 68 inches Find the length and width?
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
Can you use square inch tiles to make a helipad that is a rectangle with a perimeter of 9 inches?
Could be. Let's say the rectangle is 3.5 in by 1 in; then it would take 3 and one-half tiles.
What is the length and width of a table top that is haped like a rectangle whose perimeter is 73.4inches and the length is 4.7 inches?
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.
