0
What is the perimeter of a rectangle with length 3 yd and width 7 yd?
Wiki User
∙ 10y ago
Perimeter = 2*(L+W) = 2*(3+7) = 2*10 = 20 yards.
By the way, conventionally, the length is the bigger dimension.
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
The length of a rectangle is three times its width If the area of the rectangle is 108yd2 find its perimeter?
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
What is the length of a rectangle with an area of 12 yd and a width of 3 yd?
length = 12/3 = 4 yards
What is the perimeter of a rectangle that you s 5 yd long and 3 yd wide?
well the formula is p=2(l+w) p stands for perimeter l stands for length w stands for width P= l+l+w+w =5+5+3+3 = 16
Is converting sq ft to sq yd the same formula as sq yd to sq ft?
Yes. convert to the common unit of measurement (e.g. ft to yd) and then multiply length times width.
A rectangle field that is 119 square yards in area is to covered by sod. it is known that the field is 3 yards longer than twice the width. find the dimensions of the field. how do i do this?
It is given that the length is twice the width plus 3 yards; this can be written as a formula: Length = 2 × Width + 3 To calculate the area of a rectangle the formula is: Area_rectangle = Length × Width Substitute for Length in the above formula by the given expression involving Width → Area = Length × Width = (2 × Width + 3) × Width = 2 × Width² + 3 × Width But the area is given as 119 sq yd. If I now write w for Width, this gives: 2w² + 3w = 119 sq yd → 2w² +3w - 119 = 0 Which is a quadratic which can be solved either by using the formula or by factorising: It does factorise: the factor pairs of 119 are 1 × 119 and 7 × 17. One bracket will have (2w ...) and the other will have (w...). As the 119 is negative, there are effectively four pairs of numbers that could be fitted into the brackets: {-1, 119}; {-7, 17}; {7, -17}; {1, 119}. There is one pair which will fit so that when multiplied out gives the quadratic. A quadratic will always have two solutions; as one of the numbers above is negative and one positive, the two solutions will comprise of one positive and one negative value for w (Width); as a length must be positive, the negative solution cannot work and the positive solution is the required Width, from which the Length can be calculated (as above).
How long is the diagonal of a rectangle with the length of 30 yd and the width of 30 yd?
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
What is the perimeter for basketball court is 30 yards wide and 40 yards long?
Perimeter is the length round the outside. A basketball court is a rectangle, so: perimeter = 2 x (length + width) = 2 x (30 yd + 40 yd) = 2 x 70 yd = 140 yd
The length of a rectangle is three times its width If the area of the rectangle is 108yd2 find its perimeter?
Well, L=6 and W=18If you do the math you get (6*2)+(18*2)=12+36=48Your final answer 48 yd. The perimeter is 48 yd.
The perimeter of a soccer field is 310 yd. The width is 5 yd more than half the length. Find the length and the width.?
49
What is the length of a rectangle with an area of 12 yd and a width of 3 yd?
length = 12/3 = 4 yards
What is the area of rectangle that is 12.4 yd 12.4 yd 6 yd 6 yd?
The area of a rectangle is its length by its width, so 12.4x6 is 74.4 yards squared
What is the perimeter of 9 yd long x 11 yd wide?
To calculate the perimeter of a rectangle simply add the length and width then double your answer. In this case P = (9 + 11) x 2 = 20 x 2 = 40 yds
How many yards of fencing will you need for 20yrds by 15yrds?
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
What is the perimeter of a rectangle that you s 5 yd long and 3 yd wide?
well the formula is p=2(l+w) p stands for perimeter l stands for length w stands for width P= l+l+w+w =5+5+3+3 = 16
What is the perimeter of a rectangle that is 5 yd long and 3 yd wide?
16yd
What is the length of A equals 337 68 yd 2 w equals 60.3 yd?
If the figure in question is assumed to be a rectangle, If A is assumed to be its area, If W is assumed to be its width, then the length = Area / Width = 33768/60.3 = 560 yards.
Find the width of a rectangle with a length of 6 yd and a perimeter of 18 yd.?
The formula for perimeter is 2L+2W=P so 2*6+2*W=18 simplify 12+(2*W)=18 subtract across 2*W=6 i take it you can get it from here 3 for those of you who can't divide
